interesting chem question with electron config

[pistolpete007]

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Cu and Cr....are the ones that get the 3d shell filled b4 the 4s shell i believe.....but what if u have something like Zn^+1?


it is Cu and Cr right? or is it cobalt lol

also any ORBITAL can hold 2 electrons but if u have like a P SUBSHELL it holds 6 electrons and if u are given something like n=4 this has 18 electrons

 

[TeamGuo]

yea Cu and Cr are the odd balls.

Tip is look at the periodic table, one's that act weird are

Cr
Mo

Cu
Ag
Au

But Zn+1 you do the same thing as usual, write down the ground state config. and take 1 electron off. [Ar] 4s2 3d9

Your other question is correct, if you are just given n=4 , since n describes the shell it includes all of the subshells, hence number of electrons would be 18. Vs just an orbital, you can only have 2 max.

 

[pistolpete007]

ya i was kinda confused bc Zn+1 would give u the same atomic number as Cr

 

[theedaddy77]

Cr
{Ar} 4s1 3d5..... not 3s2 3d4
Cr +
{Ar} 4s1 3d4

Zn
{Ar} 4s2 3d10

Zn +
{Ar} 4s2 3d9


Also what are these oddballs one ur talking about?

BAsically u always do this write the correct state and then for plus and minus u add or subtract from the d ones not s! reason is d is farther out.... PLZ correct if wrong......... or if right plx menition

 

[TeamGuo]

Cr
{Ar} 4s1 3d5..... not 3s2 3d4
Cr +
{Ar} 4s1 3d4

Zn
{Ar} 4s2 3d10

Zn +
{Ar} 4s2 3d9


Also what are these oddballs one ur talking about?

BAsically u always do this write the correct state and then for plus and minus u add or subtract from the d ones not s! reason is d is farther out.... PLZ correct if wrong......... or if right plx menition

By odd balls = I meant sometimes you forget you do [Ar] 4s1 3d5 for Cr

since people might do [Ar] 4s2 3d4

Only those 2 groups, Cr group, and Cu group you have to grab that electron from the s orbital to satisfy the energy state. = gives you lower energy state config.

You are right on the money on your reasoning.