- Joined
- Aug 20, 2007
- Messages
- 206
- Reaction score
- 0
If you have an isosceles triangle with an area of 64 inch squared. How would you go about calculating the length of one of the sides?
If you have an isosceles triangle with an area of 64 inch squared. How would you go about calculating the length of one of the sides?
Area = (1/2)(base*height).
With an isosceles triangle, base and height are the same length -->
(side*side) or (side^2)
So...
64 = (1/2)(side^2)
side^2 = 128
side = sqrt(128) or 8*sqrt(2)
Only works when the two equal sides form a right angle... otherwise it doesn't.
Sorry, I forgot to mention this way of solving is for an isosceles right triangle....But DAT math is supposed to be simple so I don't think they'd ask for something more complicated than this.Only works when the two equal sides form a right angle... otherwise it doesn't.