Futureortho24

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Hello everyone! Question - in the kaplan flashcards, O34 says T/F the reduction of an alkyne on a metal surface (pd) results in a cis alkene

I thought that was true, but the answer on the flashcard says it is false that it forms an alkane! Am I mistaken or is there an error on the card?

THANKS!!
 
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asckwan

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Sorry to burst the bubble here, but the flash card is right. Only when paired with a "poison catalyst" (Lindlar's catalyst) or only one equivalent of H2 and Pt will it stop at a cis alkene or else it is potent enough to continue on. Hope that helps out.
 

Rook

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asckwan said:
Sorry to burst the bubble here, but the flash card is right. Only when paired with a "poison catalyst" (Lindlar's catalyst) or only one equivalent of H2 and Pt will it stop at a cis alkene or else it is potent enough to continue on. Hope that helps out.
Not an error
Asckwan is 100% correct
 
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Futureortho24

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I never heard of that - Thanks for the info! It is ok Messenger, I thought there really was an error! I will have to keep this in mind that ONLY when paired with a poison catalyst it reacts in the way I first thought!

Thanks guys!
 

slayerdeus

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Yea, sometimes you gotta sit back and remember that you are on a forum which anyone can reply to you. The flashcard is indeed correct. When reducing an alkyne using H2/platinum it is syn addition but it doesn't stop at the alkene, it goes all the way through to the alkane.
 

dat_student

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Futureortho24 said:
Hello everyone! Question - in the kaplan flashcards, O34 says T/F the reduction of an alkyne on a metal surface (pd) results in a cis alkene

I thought that was true, but the answer on the flashcard says it is false that it forms an alkane! Am I mistaken or is there an error on the card?

THANKS!!
There is a hidden assumption: you have an excess amnt of H.
 
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