Least Substituted Elimination?

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jhanago

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I read somewhere on this site that an E2 elimination would favor the least substituted carbon, yet my textbook states otherwise...



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I think that it's a typo. It should have been hoffman product or anti-zaitsev product.

Whenever you have a tertiary alkyl halide and a bulky base then you always form HOFFMAN product (least substituted)..

That's what i think.. Anyone else??
 
I think that it's a typo. It should have been hoffman product or anti-zaitsev product.

Whenever you have a tertiary alkyl halide and a bulky base then you always form HOFFMAN product (least substituted)..

That's what i think.. Anyone else??

Problem is it's consistent throughout the whole book... even in sample problems and practice problems etc
 
First of all, E2 doesn't favor least substituted product all the time. IT usually favors most substituted product, the only exception is when you have a bulky base and tertiary alkyl halide then you will get least substituted product.

Ex - tertiary alkyl halide + bulky base = least substituted
Primary/Secondary + Bulky base = most substituted..
 
Good thought but it shows no stereochemistry. actually... in the rxn is there any chiral centers? I dont think that there is on the reactant side.


also make sure that it's anti peri planar
 
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