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I am confused about the competitive inhibition plots. Can someone explain why the slope increased? I found the below answer but it still doesn't make sense. Why would km going up increase the y intercept? If this is the case then if Km goes down wouldn't Y go up, and the slope go down? This is not what happens in non competitive plots for example. Sorry for the long post but this topic is really confusing me.
If your enzyme of choice is busy interacting with the competitive inhibitor instead of with its normal substrate, then the normal substrate changes- the APPARENT Km increases. This means that the enzyme has a LOWER affinity for it. How does this affect our Lineweaver-Burk plot? If the Km goes UP, then the denominator of the y-intercept (-1/Km) increases. This means that the x-intercept has a smaller absolute value,and shifts to the RIGHT, closer to zero. However, your Vmax stays the same(even though it may be harder to reach with all that competitive inhibitor floating around). So the net result is a steeper slope of your line.
If your enzyme of choice is busy interacting with the competitive inhibitor instead of with its normal substrate, then the normal substrate changes- the APPARENT Km increases. This means that the enzyme has a LOWER affinity for it. How does this affect our Lineweaver-Burk plot? If the Km goes UP, then the denominator of the y-intercept (-1/Km) increases. This means that the x-intercept has a smaller absolute value,and shifts to the RIGHT, closer to zero. However, your Vmax stays the same(even though it may be harder to reach with all that competitive inhibitor floating around). So the net result is a steeper slope of your line.