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Started by Zerconia2921
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draw it out it'll help you out
D----------------A-------C-------B
AB and AD are equidistant from each other. That means that A is between D and B. CD is 35 units away while AC is 15 units away. So that means that C is between A and B.
D-A + A-C = Distance between D-C
hope that helps =)
D----------------A-------C-------B
AB and AD are equidistant from each other. That means that A is between D and B. CD is 35 units away while AC is 15 units away. So that means that C is between A and B.
D-A + A-C = Distance between D-C
hope that helps =)
hahahaha no problem man.
and to prove you wrong about me being a dictionary...i have no idea how to go about that second question. Im not too big on genetics haha. damn p^2 + 2pq +q^2. and p+q=1. hope someone else can pick up the tab on that one =)
and to prove you wrong about me being a dictionary...i have no idea how to go about that second question. Im not too big on genetics haha. damn p^2 + 2pq +q^2. and p+q=1. hope someone else can pick up the tab on that one =)
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second questions is like this...
10000-9898/10000 will give you the recessive.
so 10000-9898/10000 =.01=q^2
so find q first which will be the square root of .01 which is .1
Then use p+q=1 to find the dominant, p+.1=1 so p=.9
so then use 2pq to find the heterozygote frequency...
Answer: 2(.1)(.9)=.18
10000-9898/10000 will give you the recessive.
so 10000-9898/10000 =.01=q^2
so find q first which will be the square root of .01 which is .1
Then use p+q=1 to find the dominant, p+.1=1 so p=.9
so then use 2pq to find the heterozygote frequency...
Answer: 2(.1)(.9)=.18
