second questions is like this...
10000-9898/10000 will give you the recessive.
so 10000-9898/10000 =.01=q^2
so find q first which will be the square root of .01 which is .1
Then use p+q=1 to find the dominant, p+.1=1 so p=.9
so then use 2pq to find the heterozygote frequency...
Answer: 2(.1)(.9)=.18