Math problem. Can you solve it?

[Orgodox]

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Hey guys heres a problem that I cant figure out why they got what they did so I wanted to see what other people got.

Basically the problem says:
Want to get somewhere by 1 PM which is 5 Km away. Travel at speed of 1/3 m/s and take a 10 min break what time will you have to leave to get there on time?

I did

5Km X 1000m/1Km X 3Sec/1 m X 1 hr/3600s = 50m/12hrs So 4 hours and 20 mins which means he has to leave at 8:40 AM but remember he takes a 10 min break so he needs to leave at 8:30. They say the answer is 840 and in their answer which is not much of an explanation I see that they did factor int he break so im confused.

 

[TeamGuo]

I got 8:40.

I just used the d=rt formula and found

it takes 15000 seconds for the distance then + the break time = 15600 s

which gives us 260 min = 4 hours and 20 min.

So you have to leave at 8:40

 

[drgreen]

perhaps...

(5 Km)(3s/1m)(1000m/1Km)(1hr/3600s)=4.16666 hr
Which is equivalent to 4 hours and 10 minutes (.16*60=9.6)
1:00 minus 4 hours and 10 mins=8:50, take into account the 10 min break, we get 8:40

 

[Streetwolf]

To the OP: You did 50/12 = 4 and 1/3 when it really equals 4 and 1/6. You got 4 hrs 20 minutes and you should have gotten 4 hrs 10 minutes.