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Math Question

Discussion in 'DAT Discussions' started by Doogie Howser, Apr 29, 2007.

  1. Doogie Howser

    Doogie Howser practicing since age 12 5+ Year Member

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    Jan 11, 2006
    Say there is a minor disease A that affects on average 1 of 3 people. What are the chances of randomly selecting a group of 4 people and having 1 person affected?
     
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  3. Lonely Sol

    Lonely Sol cowgoesmoo fan! 10+ Year Member

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    Dec 13, 2005
    Atlanta, GA
    Well, you know 1/3 people is effected with the diseases and 2/3 people are not effected with the disease.

    Since, there is 1 person effected out of 4, then:
    1/3*(2/3)^3 = 8/81
     
  4. Doogie Howser

    Doogie Howser practicing since age 12 5+ Year Member

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    Jan 11, 2006
    oh duh, i don't know how i missed that
     
  5. Lonely Sol

    Lonely Sol cowgoesmoo fan! 10+ Year Member

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    Dec 13, 2005
    Atlanta, GA
    Is that the right answer, besides why are you even opening a DAT text? You should be out enjoying!!
     
  6. Streetwolf

    Streetwolf Ultra Senior Member Dentist 7+ Year Member

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    Oct 25, 2006
    NJ
    But any of the 4 of them can have it so you multiply by 4 and get 32/81.
     
  7. JohnnyOU

    JohnnyOU Slow like Honey 7+ Year Member

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    Dec 27, 2003
    OKC, OK
    :laugh:
     
  8. Lonely Sol

    Lonely Sol cowgoesmoo fan! 10+ Year Member

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    Dec 13, 2005
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    Thanks, totally forgot about that!
     

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