- Joined
- Jul 23, 2003
- Messages
- 351
- Reaction score
- 0
Quick question..Hoffman eliminatin always produces terminal alkenes right? Never internal ones?
Anyone know why? Peace out 😎
Anyone know why? Peace out 😎
Why? Just want to know to make sure im not getting dummer...
Lol YOUR not getting any DUMMER man!
Hoffman elimination creates terminal alkenes DO TOO steric effects. I have educated thou! Now call me jesus![]()
My kaplan teacher told me that a bulky base like Potassium tert-butoxide produces the Hoffman elimination (less substituted alkene, & the only exception to Zaitstev's rule), are you referring to the bulkiness of the substrate or of the base? The tertiary halide with potassium tert-butoxide!
They both have a role. Since the base is large, it can only attack where it sees an opening. The whole point to this reaction is to make the leaving group large and use a large base so that the combination of the 2 will only allow either terminal or the least substituted alkenes. Thats what I was taught at least.