nmr split questions (singlet, triplet)

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joonkimdds

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  1. Pre-Dental
CH3-O-CH2-CH2-O-CH3


The correct answer is singlet and singlet.
But I think answer should be singlet and triplet.

Here is what I did.
The first C from the left has a adjacent atom with H=0 so we add one and it has singlet.

The 2nd C from the left has a adjacent carbon with H=2 so I added one and it should be triplet.

what am I doing wrong?
 
H H' H' H
| | | |
H-C-O-C'-C'-O-C-H
| | | |
H H' H' H

WOW that took me a while to draw. But count the bonds, if the Hs are more than 3 bonds apart, they won't split each other.
(count for yorself, and they should be 4 bonds apart in this molecule)
 
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H H' H' H
| | | |
H-C-O-C'-C'-O-C-H
| | | |
H H' H' H

WOW that took me a while to draw. But count the bonds, if the Hs are more than 3 bonds apart, they won't split each other.
(count for yorself, and they should be 4 bonds apart in this molecule)

I only see 3 bonds apart between H' of 2nd carbon to H' of the 3rd carbon. Maybe I am doing this wrong?
H'
|
C-C
...|
...H'
Above pic, there are 3 bonds between H' to another H'.
 
C2 and C3 are the same indeed
However, C1 would split C2 and C4 would split C3
So, you end up with
triplets (C2 splitting C1/ C3 on C4)
and Quadralit (4 peaks, C1 splitting C2, C4 splitting C3)
 
Hey,

In butane( CH3-CH2-CH2-CH3 ), don't H on C2 and C3 have the same environment and symmetry as well? How come it's not singlet?

I guess CH2 doesn't count the other CH2 on his right(due to symmetry) but there are H on the left side which is CH4.

By the way, can someone post an example with OH and how many splits each will have?

For example, in OH-CH2CH2CH2CH3, does H from OH have triplet and will it be at downstream?
 
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