Normality in GCHEM

[mario0923]

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hey guys do you know how to calculate the normality in chemistry?
I don't get what is gram equivalent...

and also is the achiever's RC supposed to be really hard...?
I was getting around 20 in cracktheDAT and datQvaults
but I just got a 15...

and...
Is the reat DAT's PAT going to look like Achiever's? I really had hard time with those low quality pictures.. I had 22~25 in cracktheDAT but I just got a 18.....

thank you!!

 

[Kingsta2426]

An example would be calculate the normality of 38g of HCl in 6.2 L of solution. The formula is gram equivalent/ L solution. So just divide 38 by 36 (molar mass of HCl) which = 1.05 then divide that by 6.2 L which = 0.17. Also note that molarity and normality can be the same value is the number of moles are equal. Hope this helps.

 

[mario0923]

An example would be calculate the normality of 38g of HCl in 6.2 L of solution. The formula is gram equivalent/ L solution. So just divide 38 by 36 (molar mass of HCl) which = 1.05 then divide that by 6.2 L which = 0.17. Also note that molarity and normality can be the same value is the number of moles are equal. Hope this helps.

what i am confused is everyone has a different way to calculate....
KBB DAT says Normality(N)=(gram of equivalent weight of solute)/(L of solution)
where gram of equivalent weight of solute=(Molar Mass)/n

so N=(Molar Mass)/(n*(L of solution)) which is not same as Molarity(M)=(n of solute)/(L of solutions)

 

[ballyhoo]

wait...all of this is confusing me and i thought i understood it!!

 

[Kingsta2426]

what i am confused is everyone has a different way to calculate....
KBB DAT says Normality(N)=(gram of equivalent weight of solute)/(L of solution)
where gram of equivalent weight of solute=(Molar Mass)/n

so N=(Molar Mass)/(n*(L of solution)) which is not same as Molarity(M)=(n of solute)/(L of solutions)

gram equivalent is same thing as # of moles notice 38/36 means 1.05 moles of HCl