Ochem difference between (CH3)3CO- NA+ and C2H5O- K+??

[kies89]

both are bulky strong base right?

and both cause E2 elimination


one of the destroyer question was
which works best to get rid of Br and make double bond

i narrowed down to these two but do not really know the differences between these two (CH3)3CO- NA+ and C2H5O- K+

help!

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[spikers220]

Both of them favor E2 and both are strong. There is only one bulky group though and that is (CH3)CO-. This one will favor the Hoffman elimination, the less substituted alkene product. The other will favor the most substituted. So I guess in my opinion it all depends on where you want the double bond.

 

[Dotoday]

Not true. Both of them are nit big bulky bases. The sodium t-butoxide (CH3)3C-Na is a big bulky base. It usually prefers Hoffman elimination over Zaitsev, meaning it preferentially forms less substituted alkene. Potassium or Sodium Ethoxide, C2H5O-K, is a smaller base, but prefers Zaitsev elimination, forms more substituted alkene. However, both if them can do E2. Hope this helps.

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