You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an alternative browser.
You should upgrade or use an alternative browser.
ochem Q, please help
Started by Questions
with ether, 2 moles of grignard react with the reactant, thus Mg+ react with halogen (I-) and form a good leaving group. eventually it leaves with CH2CH2.
That's what I think, Correct me plz if I'm wrong.
OK I just spoke to my awesome professor from undergrad...it is a reaction is an internal grignard. You make the grignard reagent on one end and attack the other end to form a double bond.
hope that helps
Last edited:
to clarify the answer,
so ICH2CH2I gets attacked by Mg-ether to form Grignard Reagent, which is ICH2CH2-MgEther, right?
Then what attacks the other end and how does the reactions happen?
Could you please help me understand what becomes what and how it attacks?
Thank you very much.
so ICH2CH2I gets attacked by Mg-ether to form Grignard Reagent, which is ICH2CH2-MgEther, right?
Then what attacks the other end and how does the reactions happen?
Could you please help me understand what becomes what and how it attacks?
Thank you very much.
okay, so the ICH2CH2-Mg grignard is formed, and another ICH2CH2-Mg attacks the I of the other, and as they are forming the double bond, the Mg on the other side of the attacked side gets kicked off??
could you please explain more detail than just throwing fragments?
i lack a lot of ochem knowledge to understand shortened versions 🙁
Thank you so much for helping!
could you please explain more detail than just throwing fragments?
i lack a lot of ochem knowledge to understand shortened versions 🙁
Thank you so much for helping!
Similar threads
- Replies
- 3
- Views
- 2K