ochem Q, please help

Started by Questions
This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

Questions

Full Member
10+ Year Member
15+ Year Member
Advertisement - Members don't see this ad
What is the product?

ICH2CH2I + Mg(ether) --> ???

the answer is CH2CH2

can someone explain please?
 
Cliff DAT 🙁

I got that question wrong too!

Only chem q that I got wrong on that practice test.

Cliff DAT prep book is too easy in difficulty, right?
 
with ether, 2 moles of grignard react with the reactant, thus Mg+ react with halogen (I-) and form a good leaving group. eventually it leaves with CH2CH2.
That's what I think, Correct me plz if I'm wrong.
 
with ether, 2 moles of grignard react with the reactant, thus Mg+ react with halogen (I-) and form a good leaving group. eventually it leaves with CH2CH2.
That's what I think, Correct me plz if I'm wrong.

OK I just spoke to my awesome professor from undergrad...it is a reaction is an internal grignard. You make the grignard reagent on one end and attack the other end to form a double bond.

hope that helps
 
Last edited:
to clarify the answer,

so ICH2CH2I gets attacked by Mg-ether to form Grignard Reagent, which is ICH2CH2-MgEther, right?

Then what attacks the other end and how does the reactions happen?

Could you please help me understand what becomes what and how it attacks?

Thank you very much.
 
okay, so the ICH2CH2-Mg grignard is formed, and another ICH2CH2-Mg attacks the I of the other, and as they are forming the double bond, the Mg on the other side of the attacked side gets kicked off??

could you please explain more detail than just throwing fragments?

i lack a lot of ochem knowledge to understand shortened versions 🙁

Thank you so much for helping!