Ochem question

Started by sakthivs
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sakthivs

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Ok so for ochem destroyer question 62 on the 2012 destroyer...the question asks which of the following reactions would yield an alkene. The answer is 2-iodobutane reacted with NaOCH3. I understand how this is a possible answer because the reactant can undergo both SN2 and E2. However why couldn't t butyl iodide reacted with CH3OH also create an alkene? isnt there a possibility of E1 in this case?
 
ya i would but i have no idea how to upload pics on here....basically in short my question is:

Will t-butyl iodide reacted with CH3OH go through both E1 and SN1? or just SN1?
 
Alcohol without heat would most likely to Sn1, not E1. If you wanted to do E1, you should use Ethanol and heat, to create a carbocation.

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The reason that CH3OH and butyl iodide DO NOT make an alkene is b/c E1 reactions cannot have a primary alkyl halide. (Butyl iodide being the primary alkyl halide).

Fun fact: E2 reactions can occur with primary alkyl halides, but Sn2 is the major.
 
The reason that CH3OH and butyl iodide DO NOT make an alkene is b/c E1 reactions cannot have a primary alkyl halide. (Butyl iodide being the primary alkyl halide).

Fun fact: E2 reactions can occur with primary alkyl halides, but Sn2 is the major.

i know butyl iodide is a primary alkyl halide, i was talking about t-butyl iodide (its a tertiary alkyl halide). I think Dotoday answered my question...so in this case if t-butyl iodide was reacted with just CH3OH (no heat) then it will just result in a SN1 reaction and NOT an E1 reaction?