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Yea....it looks like 2-butene..however, couldnt all teh answers be correct, b/c all ofthem are ALKENES, and we can draw the H's as comming into the page or going out fo the page, so that will be cis/trans ISOMERISM, right ?
No.
cis/trans are designation between different atoms attached to a carbon carbon double bond to clarify their relative positional difference. For the ethene, the 4 hydrogens attached to the double bonded carbons are identical thus cis and trans designation serves no purpose.
The answer can only be 2-butene because that allows both cis and trans conformation.
The cyclohexene can only exist in cis conformation. However, cycloheptene and any other cyclo alkene with 7 carbons or more can exist in both cis and trans.
Draw out cyclohexene. You get cis conformation with the carbon carbon double bond.
Cycloheptene, can be drawn like cyclohexene ring (in cis) and as trans conformation with double bonded carbon with two other substitutent carbons in trans to complete the ring structure. So it won't look like a ring per se but more like a half eaten pie.
In a nutshell, anything less than 7 carbon will have so much strain in the ring formed in trans conformation, it will not keep its structure. FYI, cyclohexene in trans only exists with half life of 45 sec.
If you don't understand my half-a$$ed explanation, I suggest you reread your textbook. 🙂
For Cyclohexene would you say that the 2 hydrogens on the carbon-carbon double bond is out of the plane of the double bond and is on the same side which makes it cis?
I guess one can say that any cycloalkene bigger than and equal to 7 carbons will be "floppy" so the other carbons can be up or down making cis and trans isomers possible...yeah?