I just took an OAT exam. It can be found here: https://www.ada.org/oat/index.html Question 85: The question is which will undego an free radical bromination most rapidly. The answer said it was CH4 but i thought it would be (CH3)3CH. Cause it forms a tertiary (most stable) carbocation. Can someone explain why free radical bromination is fastest with methane or if this is a mistake because it basically goes against everything iver learned in ochem, thanks!