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BoneMental

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A buddy of mine and I keep disagreeing on this point.

In regards to factors that affect rate constant (not equilibrium constant, but rate constant), we both know that temperature and catalysts are examples. What about concentration?

I argue that its not in the Arrhenius equation, and doesn't affect the rate constant. My friend is thinking practically that it would. I don't really know what's right.

Can someone clarify this? I've tried searching in the forums (and the interwebz), but I'm getting a lot of mixed answers...😱
 
I'm guessing this is one of those topics that will get a lot of posts.

My understanding - rate constant, k, is affected by temperature and activation energy/presence of catalysts. The rate itself depends on more variables, like concentration (more molecules bumping into each other) and reaction order. So maybe your friend is thinking about reaction rate itself, not the rate constant.
 
I'm guessing this is one of those topics that will get a lot of posts.

My understanding - rate constant, k, is affected by temperature and activation energy/presence of catalysts. The rate itself depends on more variables, like concentration (more molecules bumping into each other) and reaction order. So maybe your friend is thinking about reaction rate itself, not the rate constant.

'Twas what I told him!
 
yes concentrations affect the RATE but not the RATE CONSTANT (k).
 
yes concentrations affect the RATE but not the RATE CONSTANT (k).

^^ this.

Of all the MCAT material I've run through, rate constant Kx changes only with temperature. So far, this assumption for MCAT has gotten me through all the FLs. I don't think it will hold up for all cases though.

Catalysts lower activation energy, and I believe help stabilize the transition state. Catalysts can speed up reactions by a HUGE amount, and help the forward and reverse reactions equally.

Playing with temperature will mess with both the reaction rate and rate constant. If the system is in equilibrium, consider effects and Le Chatlier as well; if the reaction is exothermic, increasing temperature will decrease the amount of product formed, as the system is responding to the stress of heat.
 
In regards to factors that affect rate constant (not equilibrium constant, but rate constant), we both know that temperature and catalysts are examples. What about concentration?

Based on the knowledge one learns in general chemistry, temperature is the only thing that can affect the form of the rate constant. Catalysts come along and alter the required temperature, which allows a larger proportion of molecules to participate in the reaction.

However, if you get really carried away, I suspect that you will find that concentration does affect the rate constant, but it's likely a second-order effect and beyond the scope of information on the MCAT. I would probably just focus on understanding the rate law and ignore whatever change concentration has on rate constants. It's not going to have any significant effect.
 
Factors that affect the rate of reaction are :

1)physical state of reactants, surface area of reactants.
2) initial concentration of reactants.
3) temperature of reaction.
4) presence of catalyst and inhibitor.

With that being said, the only ones that affect the rate constant are those that are not part of the reaction. This is only the temperature. For example, initial concentration of reactants would affect the reaction rate but not the rate constant because according to the equation (Rate=K [A]^n ^B) , the more of intial concentration, the more the rate is going to be and thus K will be constant because both increase together. But for example, if there is an increase in temperature, only the rate will change and increase while the concentration will remain constant and therefore the K constant will have to increase since increase in temperature does not affect the concentration. Presence of catalyst or inhibitor does not affect the rate constant because the more of a catalyst there is, the more the concentration of moles are and vice versa. And since catalysts increase the rate of reaction, the rate of reaction will increase with increasing catalysts and thus with increasing the concentration or vice versa with the inhibitors; hence, the rate constant will stay constant.
 
I think this discussion is on track vis-a-vis concentration and temperature. Concentration affects reaction rate but not the rate constant while temperature does change rate constant.

The rate constant reflects the fraction of reagent, if you picture the distribution of molecular energies, with sufficient energy to create activated complex. The proportionate fraction increases with temperature by shifting the distribution of molecular energies rightward. At greater concentration, the curve represents more molecules, but there are more present with both less and more energy than required, so the rate constant doesn't change, though reaction rate, expressed as change in concentration with time does change reflecting the greater amount of reagent, and concentration appears on its own in the rate expression reflecting its effect separate from rate constant.

However, remember you cannot get a rate expression from stoichiometry. Rate expressions have to be empirically determined regarding which reagent concentrations affect rate. This is a top ten favorite MCAT theme. Only if the component is present in the activated complex of the rate determining step will it appear in the rate expression. For example, SN1 and SN2 substitution both have the same reaction stoichiometry, but in SN1 substitution only the substrate concentration appears in the rate expression because carbocation formation is the rate determining step, but in SN2 substitution both the nucleophile and the substrate are present in the rate determining step and both affect reaction rate.

Where the discussion seems to be wandering a bit is to understand the role of a catalyst. It doesn't make sense to say that a catalyst affects rate constant because a catalyst presents a reaction with a completely new reaction mechanism, so you get an entirely new rate expression, or a simple general chemistry rate expression may not be applicable at all. There is a lot of complexity with catalysts, especially enzyme catalysis, and their kinetics because enzyme catalysts may be saturable so there isn't a linear response between reaction rate and concentration. Even in general chemistry because a catalyst is often a different phase, such as the palladium or bentonite catalysts often used, the kinetics are nonhomogeneous which is not chem 101. Complexities aside, if catalysis is homogeneous and nonsaturable you would still have a completely new rate expression with a new rate constant, unrelated to the other, basically, and possibly with different concentration terms, because a catalyst affects reaction rate by presenting a reaction with a new pathway or mechanism.
 
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