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My textbook says C-H bonds have a negligible dipole moment b/c their electronegativities are essentially same. However, C-Cl bonds have a large electronegative difference and therefore accounts for most of dipole moment in CH3Cl. Okay, I looked at the values from the electronegativity table: C= 2.5, Cl=3.0, and H=2.1. Why is there so much discrepancy between the electronegativity of the C-H and the C-Cl bonds if their electronegativities only differ by 0.1? The difference between electronegativity in C-H is 0.4 and the difference between C-Cl is 0.5, but they make a point of telling you that C-Cl is much more polar .. why?
Here is something that I actually learned in my Biology class about electronegativity(EN):
If two atoms have a difference in EN that is less than 0.5 it is non- polar.
If two atoms have a difference in EN that is from 0.5 - 2 they are polar.
If two atoms have a difference in EN that is more than 2 then they are ionic.
So i see how a C-H bond would be considered non-polar and a C-Cl bond will be
considered polar even where there is just a 0.1 difference. But I want to understand this better. Can someone explain it better than this rule? (I also know this rule has exceptions like SiF4 and CaS...)
Here is something that I actually learned in my Biology class about electronegativity(EN):
If two atoms have a difference in EN that is less than 0.5 it is non- polar.
If two atoms have a difference in EN that is from 0.5 - 2 they are polar.
If two atoms have a difference in EN that is more than 2 then they are ionic.
So i see how a C-H bond would be considered non-polar and a C-Cl bond will be
considered polar even where there is just a 0.1 difference. But I want to understand this better. Can someone explain it better than this rule? (I also know this rule has exceptions like SiF4 and CaS...)