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Which is the correct order from lowest to highest field for the chemical shifts of the numbered sets of protons in the H NMR spectrum of this compound..
BrCH2OCH2CH3
^A ^B ^C
Okay..the right answer is A<B<C. I thought the right answer was C<B<A
I thought the higher the ppm the higher the field..so then the H's in the middle of Br and O would be in the highest field and the H's on the methyl at the end would be at the lowest field?
BrCH2OCH2CH3
^A ^B ^C
Okay..the right answer is A<B<C. I thought the right answer was C<B<A
I thought the higher the ppm the higher the field..so then the H's in the middle of Br and O would be in the highest field and the H's on the methyl at the end would be at the lowest field?
