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orgo question
Started by hope_to_match
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Since it's in ether it is in an aprotic solvent which will only be sn2 or e2, so no carbocation or rearrangements. And it is sn2 because hcl is a strong nucleophile. Hope this helps
thanks it does..
i was confusing this with a reaction with just HCl with no ether. In that case there would be rearrangement right? It's rxn#1 on the alkene list from Chad..am I correct?
Yep you are correct!
ok thanks. i have to make sure not to confuse the two 😎 in the future
Also, on that reaction, the Cl is less selective than br so you will get a mixture of products opposed to the Br that will have the most substituted carbon being the location the halogen (Br) is added.
doesnt that only apply to free radical halogenation?
True, I guess I just assumed they were the same since the carbocation and radicals get stabilized with the same effects. I bet you are right, the radicals must be a special case. Good call.
well for free radical halogenation the reactants are different (Br2/CL2 with light or heat or ROOR)
no problem. i think discussing things makes this stuff stick if you know what i mean
