Compounds without charge always have a total oxidation number of zero.
Then you follow the rules in assigning oxidation states: FHO765 (order of precedence), and their respective values in order are -1, +1, -2, -1, -2, -3.
Take acetic acid, for instance (CH3-COOH)
C-C bonds are equally electronegative, therefore in accounting their oxidation state, they have no effect on each other.
hydrogens take precedence over everything else in the molecule, therefore assign +1 to all Hs.
oxygens are next in the order of precedence, therefore assign -2 to all Os.
calculate the oxidation state of the methyl carbon: it is bound to 3 hydrogens (+1 * 3 = +3), therefore it has an oxidation state of -3 (must sum to 0).
calculate the oxidation state of the carboxylic acid carbon: it is bound to 2 oxygens (one of which has a -2 oxidation state, and the other bound to a hydrogen has a -1 oxidation state (-2 + 1 = -1), therefore this carbon has an oxidation state of +3 (must sum to 0).
This site uses cookies to help personalize content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies and terms of service.