- Joined
- May 22, 2004
- Messages
- 1,285
- Reaction score
- 1
when heated, solid mercury oxide decomposes into gaseous mercury and oxygen gas, reaching equilibirum at a temperature of 740K and pressure of 15 atm, as the following rxn equation shows
2HgO (s) + heat ---> 2Hg (g) + O2 (g)
At equilibrium, the partial pressure would be pHg(g) : pO2(g) ??
the correct answer is 1 atm: 0.5 atm .
But I am not sure how to derive to this answer. I first throught it's 2:1 since the mole ratio of Hg and O2 is 2:1. Anyone know how to solve it correctly?
2HgO (s) + heat ---> 2Hg (g) + O2 (g)
At equilibrium, the partial pressure would be pHg(g) : pO2(g) ??
the correct answer is 1 atm: 0.5 atm .
But I am not sure how to derive to this answer. I first throught it's 2:1 since the mole ratio of Hg and O2 is 2:1. Anyone know how to solve it correctly?