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How is permutation different from combination?
How is permutation different from combination?
Ha im not very good at both Permutation or Combination but I think you have it backwards. I believe in permutation, order does not matter? so confusing?
I have no idea how to do this problem. Can anyone help?
How many different ways can a data set consisting of 6, 0, 0, 1, 0,1 be arranged?
It's hard to give a good formula on a message board but the answer is:Im usually pretty good at math, but this one has me stumped. it has been five years since i took AP stats back in high school, so maybe thats why i dont remember... anyway, in this case order clearly matters, so it would be a permutation. but its not as simple as just using the equation i posted earlier. since some of the items in the set are identical some of the answers would overlap for instance ... 6, 0', 0,1,0,1 would be same as 6,0,0',1,0,1 right???
STREETWOLF where are youuuuu???
It's hard to give a good formula on a message board but the answer is:
6! / 3!2! = 60
The 6! sorts them in any order. The 3! removes the repeats caused by the 3 identical 0s. The 2! removes the repeats caused by the 2 identical 1s.
In general for this exact type of problem you would do the # of elements factorial in the numerator. In the denominator you want to have a bunch of factorials. Each factorial represents a unique element with a repeat. Of course you could list EVERY element but the ones that occur once would be 1! which equals 1 so that's pretty useless. For the ones that repeat, you count up the # of times they repeat and put that number factorial in the denominator.
Another example is to ask how many ways you can arrange the letters in the word MISSISSIPPI. There are 11 letters. The I repeats 4 times as does the S. The P repeats twice.
11! / 4!4!2! = 34,650. That's a lot of ways.
Yeah sure. Got one more big test Monday. After that I'm finally free of D1 and get 2 months off 🙂. That'd be a good time to ask questions.