The question boils down to a ratio of [H+] at pH = 6 to [H+] at pH = 4. The 100 part comes from the log scale (which you clearly got right). The next step is to consider whether there is more hydronium at pH = 4 or pH = 6. The lower pH has greater [H+], so the correct answer is a ratio of (a smaller number) : (a bigger number), so it must be 1 : 100.
The fraction must be set up in the ration described in the passage.
The question boils down to a ratio of [H+] at pH = 6 to [H+] at pH = 4. The 100 part comes from the log scale (which you clearly got right). The next step is to consider whether there is more hydronium at pH = 4 or pH = 6. The lower pH has greater [H+], so the correct answer is a ratio of (a smaller number) : (a bigger number), so it must be 1 : 100.
The fraction must be set up in the ration described in the passage.
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