There is one other not commonly asked deactivator that is ortho/para directing...in addition to halogens and -NO...but I can't think of it...just something to keep in mind.
There is one other not commonly asked deactivator that is ortho/para directing...in addition to halogens and -NO...but I can't think of it...just something to keep in mind.
Phenol's acidity is increased when EWG is present on the ring. This is because once the proton/hydrogen from the oxygen is removed, the conjugate base is stablized by the electron withdrawing group on the ring such as halogen. This is what makes the phenol acidic. EWG on O/P position will yield more acidic product via resonance stablization compared EWG on the meta position via induction.
in aromatic molecules,
the acidity increase by adding an electron with-drawing group to the ring. it could be NO2 or Br etc.
the basisity of the ring on the other hand increase with the electron donating groups such as NH2
what if you have to groups attached to the aromatic ring, let's say NO2 and NH2 and you are asked to add another one to the ring...make sure you go by the configuration of electron donating/activating group in this case NH2. so you need to think ortho and para in this case
KNOW pages 321, 324 and 326 of the Kaplan blue book as well, you don't regret it😀
best of luck
Phenol's acidity is increased when EWG is present on the ring. This is because once the proton/hydrogen from the oxygen is removed, the conjugate base is stablized by the electron withdrawing group on the ring such as halogen. This is what makes the phenol acidic. EWG on O/P position will yield more acidic product via resonance stablization compared EWG on the meta position via induction.
If NO2 is M directing EWG, the why in the kaplan book says that methyl group directs substitution products for M is only for 3%, but ortho and para it is 63% and 34% respectively??
Anyone know this?
Thanks