At a specific depth in a swimming pool, a barometer measures the total pressure to be twice that of atmospheric pressure. if the barometer is now submerged to a depth that is twice its initial depth, by how much does the total pressure increase?
A by 50%
B by 100%
C by 200%
D by 300%
Answer is A
Im not sure because k so P(Total)= P(atm) + P(gauge)
here we know that P(Total)= 2P(atm) and this is at the inital specfic depth
Then final pressure we have an increase in depth by 2 and so P(final)= 2P(atm) + 2P(gauge)
and now Im lost
A by 50%
B by 100%
C by 200%
D by 300%
Answer is A
Im not sure because k so P(Total)= P(atm) + P(gauge)
here we know that P(Total)= 2P(atm) and this is at the inital specfic depth
Then final pressure we have an increase in depth by 2 and so P(final)= 2P(atm) + 2P(gauge)
and now Im lost