pie bond question

[joonkimdds]

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which of the following statements about pie bonds is incorrect?

a) double or triple bonds contain a sigma bond and 1 or 2 pi bonds, respectively.

b) one pi bond is cylindrically symmetrical about an internuclear axis.

c) a pi bond could be formed by the overlapping of two 2p atomic orbitals in a sideways or parallel manner.

d) a sigma bond is generally stronger than a pi bond.

e) a sigma bond could not be formed by the overlapping of two sp^n(n=1,2, or 3) hybrid ortitals.

first of all, i know that only single bond is single bond and 2nd and 3rd bond of double, triple bonds are sigma bonds so i know that A is correct.

could u explain the rest of them for me plz?

 

[Hyphae]

which of the following statements about pie bonds is incorrect?

a) double or triple bonds contain a sigma bond and 1 or 2 sigma bonds, respectively.

b) one pie bond is cylindrically symmetrical about an internuclear axis.

c) a pie bond could be formed by the overlapping of two 2p atomic orbitals in a sideways or parallel manner.

d) a sigma bond is generally stronger than a sigma bond.

e) a sigma bond could not be formed by the overlapping of two sp^n(n=1,2, or 3) hybrid ortitals.

first of all, i know that only single bond is single bond and 2nd and 3rd bond of double, triple bonds are sigma bonds so i know that A is correct.

could u explain the rest of them for me plz?

uh.. some typos..

a) double or triple bonds contain a sigma bond and 1 or 2 sigma bonds, respectively.

d) a sigma bond is generally stronger than a sigma bond.

once you fix those then maybe we can help?

oh and its pi not pie 😉

 

[joonkimdds]

uh.. some typos..

a) double or triple bonds contain a sigma bond and 1 or 2 sigma bonds, respectively.

d) a sigma bond is generally stronger than a sigma bond.

once you fix those then maybe we can help?

oh and its pi not pie 😉

fixed 😀
now~ show me what u got 🙂

 

[joonkimdds]

help~~~ me! plz~

 

[deleted100801]

mmmmmmmmmmmmmmmm i like cherry pie.

 

[naivegrl124]

The answer is E I believe. C and D are plainly facts in any textbooks. B could also be untrue but since Pi bond are overlap you can picture it to have a center with a lobe on top and a lobe on a bottom giving it cylindrical symmetry. Think hamburger buns, the top peice and the bottom peice and the middle or the meat is the nucleus axis. As for E, it is the most likely answer since sigma ponds are head to head overlap of hybrid orbitals (sp or sp2). Hope this helps! lol I don't know why you studying so early for this exam, its going to fly right by your head when you take it in 2 years. Ahh asians are overachievers lol!

 

[joonkimdds]

The answer is E I believe. C and D are plainly facts in any textbooks. B could also be untrue but since Pi bond are overlap you can picture it to have a center with a lobe on top and a lobe on a bottom giving it cylindrical symmetry. Think hamburger buns, the top peice and the bottom peice and the middle or the meat is the nucleus axis. As for E, it is the most likely answer since sigma ponds are head to head overlap of hybrid orbitals (sp or sp2). Hope this helps! lol I don't know why you studying so early for this exam, its going to fly right by your head when you take it in 2 years. Ahh asians are overachievers lol!

I also thought that E is the answer but the answer is B.
if there is C connected to 2 of the H with single bonds each then double bond to other C, then that's sp2 hybridization with 120degree correct?
since there is double bond, one of them is sigma and another one is pi bond.
Thus making E untrue, but for some reason E is true and B is untrue 🙁