Please help me solve this...

[busupshot83]

Based on the balanced chemical equation shown below, what volume of 0.250 M K2S2O3 (aq) is needed to completely react with 12.44 mL of 0.125 M KI3 (aq)?

2S2O3 (aq) + I3 (aq) --> S4O6 (aq) + 3I (aq)

a) 6.22 mL
b) 12.4 mL
c) 49.8 mL
d) 3.11 mL

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I'd appreciate it if someone can walk me through the problem .

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[calbear14]

I got B but I'm not sure if it's right.

 

[calbear14]

This is how I got it:

.01244L x .125M = .001555 mol KI3

.001555 mol x 2 = .00311 mol S2O3 b/c of mole ratio in balanced equation.

.00311 mol S2O3 x 1L/.250mol = .01244L or 12.44mL of K2S203
(I used the molarity of K2S2O3 to find liters needed)

Hope this helps.

 

[x-linked]

Based on the balanced chemical equation shown below, what volume of 0.250 M K2S2O3 (aq) is needed to completely react with 12.44 mL of 0.125 M KI3 (aq)?

2S2O3 (aq) + I3 (aq) --> S4O6 (aq) + 3I (aq)

a) 6.22 mL
b) 12.4 mL
c) 49.8 mL
d) 3.11 mL

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I'd appreciate it if someone can walk me through the problem .

the equation is not balanced

 

[busupshot83]

the equation is not balanced

2S2O3 (aq) + I3 (aq) --> S4O6 (aq) + 3I (aq)

Yes it is:

4 S on left; 4 S on right
6 O on left; 6 O on right
3 I on left; 3 I on right

 

[busupshot83]

This is how I got it:

.01244L x .125M = .001555 mol KI3

.001555 mol x 2 = .00311 mol S2O3 b/c of mole ratio in balanced equation.

.00311 mol S2O3 x 1L/.250mol = .01244L or 12.44mL of K2S203
(I used the molarity of K2S2O3 to find liters needed)

Hope this helps.

Thanks bud.

 

[x-linked]

2S2O3 (aq) + I3 (aq) --> S4O6 (aq) + 3I (aq)

Yes it is:

4 S on left; 4 S on right
6 O on left; 6 O on right
3 I on left; 3 I on right

it should be 6 4 3 12 if you dont believe, fine. i finished my dat already, i am just helping you

 

[luder98]

it should be 6 4 3 12 if you dont believe, fine. i finished my dat already, i am just helping you

You could be a little more helpful if you tell us why.

busupshot83,
Could you double-check on the prob? I never saw KI3 nor K2S2O3. The oxidation numbers don't seem to work out correctly.

 

[calbear14]

You could be a little more helpful if you tell us why.

yah, I still feel like I'm missing something.

 

[lnn2]

yah, I still feel like I'm missing something.

yeah, your brain j/k

 

[calbear14]

yeah, your brain j/k

teeheehee. too funny

 

[lnn2]

Based on the balanced chemical equation shown below, what volume of 0.250 M K2S2O3 (aq) is needed to completely react with 12.44 mL of 0.125 M KI3 (aq)?

2S2O3 (aq) + I3 (aq) --> S4O6 (aq) + 3I (aq)

a) 6.22 mL
b) 12.4 mL
c) 49.8 mL
d) 3.11 mL

---

I'd appreciate it if someone can walk me through the problem .

I don't think that you have to do any calculations to solve this question.

Base on the balance equation: there're 2 mole of S2O2 and 1 mole of I3 in the rxn. The ratio is 2:1 of S2O2:I3 (or K2S2O2:KI3)

Given M: 0.250 M K2S2O2 vs 0.125 M KI3 hence also in the ratio of 2:1 of S2O2:I3 (or K2S2O2:KI3)

So, since both of the ratios are equal (hence S2O2=I3) then you have to use the SAME volume of K2S2O2 as volume of KI3, which is 12.44mL for the balanced rxn to occur.

The equation is Balanced!

 

[calbear14]

I don't think that you have to do any calculations to solve this question.

Base on the balance equation: there're 2 mole of S2O2 and 1 mole of I3 in the rxn. The ratio is 2:1 of S2O2:I3 (or K2S2O2:KI3)

Given M: 0.250 M K2S2O2 vs 0.125 M KI3 hence also in the ratio of 2:1 of S2O2:I3 (or K2S2O2:KI3)

So, since both of the ratios are equal (hence S2O2=I3) then you have to use the SAME volume of K2S2O2 as volume of KI3, which is 12.44mL for the balanced rxn to occur.

The equation is Balanced!

thnx, makes sense. Glad that at least one of us has a brain

 

[lnn2]

thnx, makes sense. Glad that at least one of us has a brain

glad that I could help I was surprised that I could solve it thought my brain was fried it's been a long time since I had gchem. who knew, my brain's still functioning

 

[x-linked]

2S2O3 (aq) + I3 (aq) --> S4O6 (aq) + 3I (aq)

if this were balanced, then S2O3 lose 4 electrons( i am assuming S4O6 has 0 charge, i have no idea) I3 gain 3 electrons, so the equation is NOT balanced