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pls help...very imp quest
Started by reni
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hi,
which formula is corecT???
A+T+G+C=100% OR A+T=G+C
both are correct!
can anybody explain the difference between canine guidance and group function.
In canine guidance there would not be contact of posterior teeth and the opposite ,contact of all teeth on working side would be group function. canine guidance with contact cause wearing and anything else which it can affect??
correct me if i am wrong .
thanks in advance
In canine guidance there would not be contact of posterior teeth and the opposite ,contact of all teeth on working side would be group function. canine guidance with contact cause wearing and anything else which it can affect??
correct me if i am wrong .
thanks in advance
hi,
which formula is corecT???
A+T+G+C=100% OR A+T=G+C
A+T+G+C=100% IS correct
A=T G=C so second cannot b correct
correct me if im wrong
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A+T+G+C=100% IS correct
A=T G=C so second cannot b correct
A+T=G+C
so i think both are correct
Canine Guidance: in Lateral Excursion, only canine contact and rest of the teeth are free of contact on that side.
Group function, in lateral excursion not only canian but also premolars and sometimes molars are in contact.
Group function, in lateral excursion not only canian but also premolars and sometimes molars are in contact.
I understand that could be tell me if in case person doesnt have canine will it affect lateral movement and what all the other ill affects can we see.
we can see both canine guidance and group function at a time on lateral working side?
final question if in case we change anterior guidance how will it affect ,IC ,CR , PCP, RP, EE ,RP.
I appreciate your help.
we can see both canine guidance and group function at a time on lateral working side?
final question if in case we change anterior guidance how will it affect ,IC ,CR , PCP, RP, EE ,RP.
I appreciate your help.
A+T=G+C
so i think both are correct
a sequence may not contain equal amt of all four...amt of individual base pairs may
a=t, g=c lets take for example g is 20 then c will also be 20 so,g+c=40 the remaining 60 will be equally divided by a &t then it will be 30 each then a+t will be 60 and g+c will be 40
only a+g(purine)=t+c(pyrimidine)
hope i didn confuse....correct me if im wrong
1.Chargaffs Rules
1. Base composition of DNA differs from species to species
2. In each species, however, the # of adenine (a) equals the # of thymine (T).
Also # of G = # of C
3. sum of purines (A+G) = sum of pyrimidines (T+C)
2. Complementary Base Pairing
-purines = pyrimidines Total purines [A]+[G] = Total pyrimidines [C]+[T]
-concentration of adenine and thymine are equal as are guanine and cytosine.
the ratio of A+T:C+G does not necessarily equal one (note this point)
Therefore, A pairs with T and C pairs with G in DNA
the thymine - adenine pair interacts through two hydrogen bonds represented as (T=A) and that the cytosine-guanine pair interacts through three hydrogen bonds represented as (C=G).
therefore,A+T=C+G is incorrect
Hope this helps,
1. Base composition of DNA differs from species to species
2. In each species, however, the # of adenine (a) equals the # of thymine (T).
Also # of G = # of C
3. sum of purines (A+G) = sum of pyrimidines (T+C)
2. Complementary Base Pairing
-purines = pyrimidines Total purines [A]+[G] = Total pyrimidines [C]+[T]
-concentration of adenine and thymine are equal as are guanine and cytosine.
the ratio of A+T:C+G does not necessarily equal one (note this point)
Therefore, A pairs with T and C pairs with G in DNA
the thymine - adenine pair interacts through two hydrogen bonds represented as (T=A) and that the cytosine-guanine pair interacts through three hydrogen bonds represented as (C=G).
therefore,A+T=C+G is incorrect
Hope this helps,
1.Chargaffs Rules
1. Base composition of DNA differs from species to species
2. In each species, however, the # of adenine (a) equals the # of thymine (T).
Also # of G = # of C
3. sum of purines (A+G) = sum of pyrimidines (T+C)
2. Complementary Base Pairing
-purines = pyrimidines Total purines [A]+[G] = Total pyrimidines [C]+[T]
-concentration of adenine and thymine are equal as are guanine and cytosine.
the ratio of A+T:C+G does not necessarily equal one (note this point)
Therefore, A pairs with T and C pairs with G in DNA
the thymine - adenine pair interacts through two hydrogen bonds represented as (T=A) and that the cytosine-guanine pair interacts through three hydrogen bonds represented as (C=G).
therefore,A+T=C+G is incorrect
Hope this helps,
thanks a lot...thats wat i was trying to explain wid an example
hi positive_doc
its great explanation
thanks
its great explanation
thanks
hi,
thnks all.......
For eg,
a=10, t=40, g=40 and c=??? on the complimentary strand of Dna
c=10
c=50
c=40
i m not sure with this question guys........but this kind of question was there in discussion thread which was deleted by our moderators n its very very imp question............so pls answer
thnks all.......
For eg,
a=10, t=40, g=40 and c=??? on the complimentary strand of Dna
c=10
c=50
c=40
i m not sure with this question guys........but this kind of question was there in discussion thread which was deleted by our moderators n its very very imp question............so pls answer
thanks for the post positive _doc,meebo
thnks all.......
For eg,
a=10, t=40, g=40 and c=??? on the complimentary strand of Dna
c=10
c=50
c=40
A+G=T+C
C=10.
This is funny either way would be 10.
correct me if i wrong
case person doesnt have canine will it affect lateral movement and what all the other ill affects can we see.
we can see both canine guidance and group function at a time on lateral working side?
final question if in case we change anterior guidance how will it affect ,IC ,CR , PCP, RP, EE ,RP.
I appreciate your help.[/QUOTE]
we can see both canine guidance and group function at a time on lateral working side?
final question if in case we change anterior guidance how will it affect ,IC ,CR , PCP, RP, EE ,RP.
I appreciate your help.[/QUOTE]
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