A Addallat Full Member 15+ Year Member Joined Jun 2, 2010 Messages 126 Reaction score 2 Points 4,601 Medical Student Jun 27, 2013 #1 Advertisement - Members don't see this ad KO2 Can somebody please explain to me why the the oxidation state of the O2 is -1 also would the oxidation state of potassium be +1? Last edited: Jun 27, 2013
Advertisement - Members don't see this ad KO2 Can somebody please explain to me why the the oxidation state of the O2 is -1 also would the oxidation state of potassium be +1?
dsoz Accepted OHSU C/O 2017 10+ Year Member Joined Apr 8, 2011 Messages 1,578 Reaction score 37 Points 4,641 Medical Student Jun 27, 2013 #2 I would think that the oxidation state of oxygen is -1/2. Just checked... http://en.wikipedia.org/wiki/Superoxide states it is -1/2 for oxygen. dsoz Upvote 0 Downvote
I would think that the oxidation state of oxygen is -1/2. Just checked... http://en.wikipedia.org/wiki/Superoxide states it is -1/2 for oxygen. dsoz
gettheleadout MD Moderator Emeritus Verified Member 10+ Year Member Verified Expert Joined Jun 23, 2010 Messages 11,799 Reaction score 2,808 Points 5,251 Resident [Any Field] Jun 27, 2013 #3 You should know that the superoxide ion is O2-. You should also know that potassium will exist as K+ in an ionic compound and so will have an oxidation state of +1. Using either of these two fact it can be deduced that the oxidation state of oxygen in the compound is -1/2. Upvote 0 Downvote
You should know that the superoxide ion is O2-. You should also know that potassium will exist as K+ in an ionic compound and so will have an oxidation state of +1. Using either of these two fact it can be deduced that the oxidation state of oxygen in the compound is -1/2.
A Addallat Full Member 15+ Year Member Joined Jun 2, 2010 Messages 126 Reaction score 2 Points 4,601 Medical Student Jun 27, 2013 #4 so wait a minute: Why is the oxidation state of superoxide -1/2 in the compound but the oxidation of superoxide just -1? Upvote 0 Downvote
so wait a minute: Why is the oxidation state of superoxide -1/2 in the compound but the oxidation of superoxide just -1?
gettheleadout MD Moderator Emeritus Verified Member 10+ Year Member Verified Expert Joined Jun 23, 2010 Messages 11,799 Reaction score 2,808 Points 5,251 Resident [Any Field] Jun 27, 2013 #5 Addallat said: so wait a minute: Why is the oxidation state of superoxide -1/2 in the compound but the oxidation of superoxide just -1? Click to expand... The charge of superoxide is always -1 but the oxidation state of each oxygen atom individually within superoxide is -1/2. Upvote 0 Downvote
Addallat said: so wait a minute: Why is the oxidation state of superoxide -1/2 in the compound but the oxidation of superoxide just -1? Click to expand... The charge of superoxide is always -1 but the oxidation state of each oxygen atom individually within superoxide is -1/2.
A Addallat Full Member 15+ Year Member Joined Jun 2, 2010 Messages 126 Reaction score 2 Points 4,601 Medical Student Jun 28, 2013 #6 Ahhhh makes sense, thank you Upvote 0 Downvote