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what is the minimum power required for a heat engine to lift a 80 kg mass 5 m in 20 s if it releases 1000 j of heat energy from its exhaust each second?
Some how you can use the formula W= Qsub h - Q sub c to calculate the answer. What examkrackers did was place Qh/t = w/t + Qc/t. I do not understand how they can rearrange the equation like this. Does power not equal work over time? To mean that would be 1000/20 = 1000 - qc. Please help with what I am not understanding about this question
Some how you can use the formula W= Qsub h - Q sub c to calculate the answer. What examkrackers did was place Qh/t = w/t + Qc/t. I do not understand how they can rearrange the equation like this. Does power not equal work over time? To mean that would be 1000/20 = 1000 - qc. Please help with what I am not understanding about this question