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Object launched at 45 degrees at an initial speed of 25 m/s....how far does it travel?
My answer key says 62.5....doesnt make sense to metime in air is 5 seconds.
Horizontal velocity is: 25m/s * cos(45) = 17.67 m/s
Distance is 88.4 meters (ignoring sig figs)
Hah, yes, thats because I'm newb. The time in the air is not 5 seconds.My answer key says 62.5....doesnt make sense to me
Thanks, its all good! Why do you multiply that by 2?Hah, yes, thats because I'm newb. The time in the air is not 5 seconds.
vertical velocity is not 25 m/s but sin(45)*25 = 17.677 m/s
So time in air is ((17.677*2)/10)=3.534 sec
So Distance is 3.534 s*17.677 m/s =62.50 meters.
Sorry about that. 😕
Gotchya. Brain farted!The total time in the air is the time up and the time down. So it takes 17.67 / 10m/s^2 to reach max height, and you need to double that for total duration in air.
Got another question for you if you dont mind. If an object is launched at 45 degrees and has a time of flight of 3 seconds, what is its range?The total time in the air is the time up and the time down. So it takes 17.67 / 10m/s^2 to reach max height, and you need to double that for total duration in air.
1.5 seconds up and 1.5 seconds down.Got another question for you if you dont mind. If an object is launched at 45 degrees and has a time of flight of 3 seconds, what is its range?