Hah, yes, thats because I'm newb. The time in the air is not 5 seconds.
vertical velocity is not 25 m/s but sin(45)*25 = 17.677 m/s
So time in air is ((17.677*2)/10)=3.534 sec
So Distance is 3.534 s*17.677 m/s =62.50 meters.
Hah, yes, thats because I'm newb. The time in the air is not 5 seconds.
vertical velocity is not 25 m/s but sin(45)*25 = 17.677 m/s
So time in air is ((17.677*2)/10)=3.534 sec
So Distance is 3.534 s*17.677 m/s =62.50 meters.
The total time in the air is the time up and the time down. So it takes 17.67 / 10m/s^2 to reach max height, and you need to double that for total duration in air.
The total time in the air is the time up and the time down. So it takes 17.67 / 10m/s^2 to reach max height, and you need to double that for total duration in air.
The total time in the air is the time up and the time down. So it takes 17.67 / 10m/s^2 to reach max height, and you need to double that for total duration in air.
If time up is 1.5 sec you know that initial vertical velocity is 15m/s (with gravity 10 m/s^2)
If vertical velocity is 15 m/s and its a 45 degree launch then horizontal is also 15 m/s.
15 m/s horizontal for 3 seconds is 45 meters.