More specifically, the picture shows that there are 3 fragments that end or begin with alanine. Use this to conclude that alanine is the cleavage point for the chain.
If there were an alanine on the C terminus, then one the resulting fragments would be alanine by itself. Since this is untrue, alanine cannot be on the 'end' of the peptide or the C terminus.
ex
ser-x-ala--his--tyr-x-ala
Cleave at x
Resulting fragments:
1. ser
2. ala--his--tyr
3. ala
With the given fragments its not possible to have ala at the c terminus.