A. 16/33

B. 32/132

C. 12/32

D. 56/132

E. 32/144

This is how I approached it. 8red+4white = 12total. Probability of picking 1red = 8/12. Probability of picking 1white (i.e., not red) = 4/11 (because there's 4 white balls and 11 balls left total since 1 red one was already picked).

Then, I multiplied. (8/12) x (4/11) = 8/33. The answer, however, is A, 16/33. I'm stumped.