QR question help- probability

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keliao

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Suppose that 3 people are selected at random from a group that consists of 6 men and 4 women. What is the probability that 1 man and 2 women are selected? i got 1/70 but answer is 3/10 . could it be a mistake 3/10?

(6C1 * 4C2) / 10C3

i got 3/10 after 2 tries, i think the question is really unclear, because if the people are selected at the same time, it's real hard to say, but say if one is picked then another is picked then the last one is pickedl, then you can work it out.
It's just simply 6/10 * 4/9 * 3/8 =72/720 or 1/10
now there are 3 ways you can arrive at this
the man can be picked first, 2nd or last
so 1/10 * 3= 3/10
hope that helps

suppose that 3 people are selected at random from a group that consists of 6 men and 4 women. What is the probability that 1 man and 2 women are selected? I got 1/70 but answer is 3/10 . Could it be a mistake 3/10?

(6c1 * 4c2) / 10c3

(6c1 * 4c2) / 10c3 = 3/10

Right equation, Wrong arithmetic