N nixon13 Full Member 10+ Year Member 15+ Year Member Joined Jan 23, 2008 Messages 252 Reaction score 1 Aug 3, 2009 #1 Members do not see this ad. Vendor sells tickets $5 for adults and $2.50 for kids. If a total of 240 people came and the total amount of money made was $800, how many adults and how many kids came?
Members do not see this ad. Vendor sells tickets $5 for adults and $2.50 for kids. If a total of 240 people came and the total amount of money made was $800, how many adults and how many kids came?
dufran3 Full Member 10+ Year Member Joined Jan 22, 2009 Messages 45 Reaction score 0 Aug 3, 2009 #2 I'm awful at math, so I wouldn't even try and setup an equation. I would take half of each, and see what it would come out to. 120 * $5 = $600 120 * $2.50 = $300 that give you a close guess... so just less than half of the 240 are adults. Depending on your answer selection, you might not have to evaluate this anymore. Upvote 0 Downvote
I'm awful at math, so I wouldn't even try and setup an equation. I would take half of each, and see what it would come out to. 120 * $5 = $600 120 * $2.50 = $300 that give you a close guess... so just less than half of the 240 are adults. Depending on your answer selection, you might not have to evaluate this anymore.
W whawha Full Member 10+ Year Member Joined Apr 1, 2009 Messages 370 Reaction score 0 Aug 3, 2009 #3 Let x = # of adults and y = # of kids Two equations can be established from whats given. x + y = 240 (simply adding up the # of heads) 5x + 2.5y = 800 (this equation is in terms of money) Just solve these equations simultaneously to get x and y, which should be the answers. I am using my phone, so, can't solve it for you now. Upvote 0 Downvote
Let x = # of adults and y = # of kids Two equations can be established from whats given. x + y = 240 (simply adding up the # of heads) 5x + 2.5y = 800 (this equation is in terms of money) Just solve these equations simultaneously to get x and y, which should be the answers. I am using my phone, so, can't solve it for you now.
R Redhead32788 New Member 10+ Year Member Joined Aug 3, 2009 Messages 5 Reaction score 0 Aug 3, 2009 #4 Try using this method; Let x= the number of childrens tickets, and (240-x)= the number of adult tickets. Setting up an equation, you should receive: 2.5x + 5(240-x) = 800 Solving for x gives 160, and (240-x) = 80. Therefore, there will 160 childrens tickets and 80 adult tickets sold. Upvote 0 Downvote
Try using this method; Let x= the number of childrens tickets, and (240-x)= the number of adult tickets. Setting up an equation, you should receive: 2.5x + 5(240-x) = 800 Solving for x gives 160, and (240-x) = 80. Therefore, there will 160 childrens tickets and 80 adult tickets sold.
suhshi Full Member 10+ Year Member Joined Dec 15, 2008 Messages 481 Reaction score 6 Aug 3, 2009 #5 Let x= adults y= kids x+y=240 5x + 2.50y=800 multiply second equation by 2 and multiply first by 5 so you get 10x + 5y= 1600 5x +5y= 1200 subtract solve for x = 80 y= 160 Upvote 0 Downvote
Let x= adults y= kids x+y=240 5x + 2.50y=800 multiply second equation by 2 and multiply first by 5 so you get 10x + 5y= 1600 5x +5y= 1200 subtract solve for x = 80 y= 160