# QR Question

#### nixon13

10+ Year Member
7+ Year Member
Vendor sells tickets \$5 for adults and \$2.50 for kids. If a total of 240 people came and the total amount of money made was \$800, how many adults and how many kids came?

#### dufran3

10+ Year Member
I'm awful at math, so I wouldn't even try and setup an equation. I would take half of each, and see what it would come out to.

120 * \$5 = \$600
120 * \$2.50 = \$300

that give you a close guess...

so just less than half of the 240 are adults. Depending on your answer selection, you might not have to evaluate this anymore.

#### whawha

10+ Year Member
Let x = # of adults and y = # of kids

Two equations can be established from whats given.

x + y = 240 (simply adding up the # of heads)
5x + 2.5y = 800 (this equation is in terms of money)

Just solve these equations simultaneously to get x and y, which should be the answers. I am using my phone, so, can't solve it for you now.

Try using this method; Let x= the number of childrens tickets, and (240-x)= the number of adult tickets. Setting up an equation, you should receive:

2.5x + 5(240-x) = 800

Solving for x gives 160, and (240-x) = 80.
Therefore, there will 160 childrens tickets and 80 adult tickets sold.

#### suhshi

10+ Year Member
7+ Year Member
y= kids

x+y=240
5x + 2.50y=800

multiply second equation by 2
and multiply first by 5

so you get

10x + 5y= 1600
5x +5y= 1200

subtract

solve for
x = 80
y= 160