QR question

  • Thread starter Thread starter 299678
  • Start date Start date
This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.
I'm not sure but...

if you have a triangle like this
http://mathworld.wolfram.com/images/eps-gif/IsoscelesTriangle_800.gif

Then the height is (0.5a)^2 + h^2 = b^2

But also area = 1/2 * a * h
so 48 = 0.5 a * h
if we solve for h = 96/a

then plug it back into
(0.5a)^2 + h^2 = b^2
so
0.25a^2 + (96^2)/a^2 = b^2

and solve for a. b = 10. The problem gives us this.

This is my guess.

Edit: I tried solving it. I don't think you can solve it using what I wrote above. So I don't know.
 
Last edited:
this is actually really easy....

that theory pthagorian? the ratio of a right triangle is 3:4:5 right?...

let's multiply this by 2 so that it becomes 6:8:10 and I'm going to put 10 as

one of the side length...

h = height b/2 = base of a half triangle:

this means that h and b/2 and 10 has to equal to 6:8:10

so just plug in... h=6 b/2=8 then you will get entire base of 16 area of 48
 
Top