QR questions

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An airline passenger is planning a trip
that involves three connecting flights
that leave from Airports A,B, and C,
respectively. The first flight leaves
Airport A every hour, beginning at
8:00 a.m., and arrives at Airport B
2(1/2) hours later. The second flight
leaves Airport B every 20 minutes,
beginning at 8:00 a.m., and arrives at
Airport C
1/(1/6) hours later. The third
flight leaves Airport C every hour,
beginning at 8:45 a.m. What is the
least total amount of time the
passenger must spend between flights
if all flights keep to their schedules?
(A) 25 min
(B) 1 hr 5 min
(C) 1 hr 15 min
(D) 2 hr 20 min
(E) 3 hr 40 min


In Township K,
1/5 of the housing
units are equipped with cable
television. If
1/10 of the housing units,
including
1/3 of those that are
equipped with cable television, are
equipped with videocassette recorders,
what fraction of the housing units
have neither cable television nor
videocassette recorders?
(A)
30
23
(B)
15
11
(C)
10
7
(D)
6
1


answers: B A

 

[BenignDMD]

First question:

assume you take the first flight which reaches airport B at 10;30am.

The scond flight leaves airport B every 20 min, or 3 times an hour. Therefore, the earliset flight you can catch will be at 10:40am. So you have to wait for 10 min. You would reach airport C 1 and 1/6 hours later, or 1 hr. and 10 min. So, you would reach airport C at 11:50.

The third flight leaves C every hour beginning at 8:45. The earliest you could catch would then be 12:45. That is a 55 min wait.

55min +10min = 1hr 5min.

 

[BenignDMD]

are you sure you typed out the second question correctly? I don't understand the answer choices either. Are they fractions?

 

[Streetwolf]

I think the OP wrote: denom over num

You have fractions 1/5, 1/3, and 1/10. The LCD is 30.

So 6/30 have cable and 3/30 have video. That's 9. But it says 1/3 of the cable users also have video. So 1/3 of 6 is 2. That means 2 of the cable users have video. So we have 4 cable users without video, 2 cable + video users, and 1 video user without cable. That's a total of 7.

The question asks how many of them don't have either. So 30 - 7 = 23.

Answer is 23/30 which is probably choice A.

 

[Jaylee777]

I get the same as street wolf...23 out of 30 dont have either