Question about finding the oxidation state

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jjunior

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Hello, im confused on how to find the oxidation state of certain compounds, like carbonyls.
for other compounds such as [Al(OH)4]-1 , the oxidation of Al is +3, bc we assign O as -2 and H as +1 right?
but for compounds like acetone COCH3CH3, how do i find the oxidation state of the carbons for example using the above method? because in TBR, they show a diff method, based on the relative electronegativity between 2 linking atoms.
thanks~🙂
 
I've been wondering the same thing. Seems like it doesn't work if you try using the first method on carbonyls...
 
Well, for organic compounds you know the structure so you have to assign oxidation states accordingly
For acetone:
Carbons one and three: Both of these carbons are attached to three hydrogens and one carbon, so the sum of the oxidation states of the atoms around these carbons is 3(+1) + 1(0) = +3, therefore these carbons have a -3 oxidation state. (hydrogen bonded to carbon is +1 and a carbon bonded to itself is 0)

Carbon 2: This carbon is bonded to one oxygen and two carbons, so the sum of the oxidation states of atoms around this carbon is 1(-2) + 2(0) = -2, therefore this carbon has an oxidation state of +2.
 
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