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question on a math problem.

Discussion in 'DAT Discussions' started by andyjl, Apr 22, 2007.

  1. andyjl

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    .234 = 130 [X]^2 * (.02)

    X = .03

    how do you solve this using approximations?
     
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  3. dentstd

    dentstd Fena Gonzales

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    Step 1: change .234 to 0.25, and 130 to 125. This gives you:

    0.25 = 125 x^2 *0.02

    Step 2: remove the decimals. 0.25 goes to 25, if 0.02 goes to 2. This gives.

    25 = 125* x^2 * 2

    step 3: reduce.

    1/2 = 5 * x^2

    1/10 = x ^2.

    Step 4: approx. 1/10 is about 1/9, and 9 is a nice squared number. X is approx 1/3. Enjoy.
     
  4. Chga

    Chga Member

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    .234= 130X^2 * .02
    .234/.02 = 2.34/.2 = 23.4/2 = 234/20 estimates to 11.5
    11.5= 130X^2
    11.5/130 estimates thought {13/130 = .1 11.5/130 = .09}
    .09= X^2
    X = .3
    :)
     
  5. andyjl

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