# question on a math problem.

Discussion in 'DAT Discussions' started by andyjl, Apr 22, 2007.

1. ### andyjl 5+ Year Member

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.234 = 130 [X]^2 * (.02)

X = .03

how do you solve this using approximations?

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3. ### dentstd Fena Gonzales 2+ Year Member

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Step 1: change .234 to 0.25, and 130 to 125. This gives you:

0.25 = 125 x^2 *0.02

Step 2: remove the decimals. 0.25 goes to 25, if 0.02 goes to 2. This gives.

25 = 125* x^2 * 2

step 3: reduce.

1/2 = 5 * x^2

1/10 = x ^2.

Step 4: approx. 1/10 is about 1/9, and 9 is a nice squared number. X is approx 1/3. Enjoy.

4. ### Chga Member 7+ Year Member

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.234= 130X^2 * .02
.234/.02 = 2.34/.2 = 23.4/2 = 234/20 estimates to 11.5
11.5= 130X^2
11.5/130 estimates thought {13/130 = .1 11.5/130 = .09}
.09= X^2
X = .3

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