Question on Statistics

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madhu10

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Prevalence of a open neural tube defect is 1 in 1000.2% of the AFP results are greater than 2.5 multiples of median (MOM). The likelyhood that the patients with a screening AFP result greater than 2.5 MOM has a fetus with open neural tube defect is .........


Can someone explains the calculations please
 
Is the "of" supposed to be "if" (after the 1000.2%)?

I think that the calculation goes like this:

For each given gestational age, the median AFP level for the population is calculated. For example (with very theoretical numbers) lets say that the population median AFP for a fetus at gestational age of 10 weeks is 10 units.

If a fetus at 10 weeks gestation has an AFP of 25 units, this is a converted into 2.5 "multiples of median".

So, the prevalence of an open neural tube defect when testing shows an AFP of 2.5 MOM is 1 in 1000.2%.

At least this is how I read this. Interestingly, there are only 512 google hits for "multiples of median", and virtually all of them are obstetrics! I think this MOM is being used as a substitute for standard deviation. Of course standard deviations are based on means. This is probably because most labs report AFP with a "<" for the lower range. Therefore no mean can be calculated. Without a mean you cannot have a standard deviation. This use of MOM probably represents a simple calculation to show dispersion (deviation) from the median.

These are all thoughts off the top of my head, so folks who know better feel free to contradict me!

Mindy
 
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