Question regarding kinetic theory of gases

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thechairman

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  1. Pre-Health (Field Undecided)
In some books i notice that KE = 3RT/2, but in other thermo books (and some MCAT passages),

KE = 3kT/2, where k is a different constant from R. I've never really seen a book explaining the difference between the two. Is this a difference in convention, or do R and k represent two really different things?
 
Perhaps different units I suppose?? not really sure ive never seen the 3kt one.
 
In some books i notice that KE = 3RT/2, but in other thermo books (and some MCAT passages),

KE = 3kT/2, where k is a different constant from R. I've never really seen a book explaining the difference between the two. Is this a difference in convention, or do R and k represent two really different things?


If I recall correctly, they are two different constants. I think you use the one with R for the KE of the gas as a whole and the k for the KE of an individual molecule in the gas. Does this sound right?
 
If I recall correctly, they are two different constants. I think you use the one with R for the KE of the gas as a whole and the k for the KE of an individual molecule in the gas. Does this sound right?

yea, that pretty much explains it. kb is the boltzman constant and is normally used in physics in relation to conservation of energy (i.e. since we are dealing with a single gas molecule, we can equate say 1/2mv^2= 3/2kbT= qV) and the units will work out.

Whereas, the equation with R is for a mol of gas (think about units for R, gas constant) and is used more in chemistry when dealing with the macroscopic level of gases.
 
If you recall,

PV = nRT, where n is the number of moles of gas

so R has units of [energy]/([moles]*[temperature])

Additionally

PV = NkT, where N is the number of molecules of gas (atoms, diatomic species, whatever)

So k has units of [energy]/[temperature]

utahjazz is right. If the average kinetic energy of a single molecule of the gas is T = (3/2)kT (assuming three degrees of freedom), then to get the total energy of the gas, you'd sum over the particles and get Ttotal = (3/2)NkT = (3/2)nRT; hence nR = Nk or k = (n/N)R, but (N/n) is avogadro's number, so k = R/NA
 
What is "degrees of freedom" in chemistry or how do you solve for it? I am asking this since it was on the last MCAT. Its been a while since I have taken chem..I am guessing its not the same thing that is used in stats.
 
Ya, I saw that as well on the MCAT and was like what the hell. I have no idea what you are talking about.
 
Long answer:

If you recall the equipartition theorem, it states that a system has an average energy of kT/2 in each quadratic degree of freedom (mode in which the gas can store the energy). A monatomic gas can store energy as kinetic energy (Vx^2, Vy^2, Vz^2), so the average energy of an atom in this gas is 3*(kT/2), and the total energy of the gas is just the number of atoms times the average energy: U = N*3*(kT/2).

A diatomic gas can store the energy in the three translational degrees of freedom and two additional modes of rotation, so they have 5 degrees of freedom. Hence the average energy of a diatomic gas is 5*(kT/2), and the energy of the total gas is U = N*5*(kT/2).

The nuance is that if a particular way of storing energy isn't expressable as a square of some variable in the expression for total energy, the theorem doesn't hold, and it may not have an average energy of kT/2. For example, the total energy of a free particle moving in three dimensions is:

U = T = Px^2/(2m) + Py^2/(2m) + Pz^2/(2m) ; where the Ps are momenta.

Each term is a square of something, so under the theorem each will have an average energy of kT/2. Thus if you're given the temperature of a gas of known composition, you could figure out the average velocity or momentum in some direction after looking up the mass on a periodic table and plugging in the given temperature. My brain's shot right now (damn micro), so I'm having trouble thinking of a nonquadratic energy that isn't a potential, and I don't think the makers of the MCAT care.

Short answer:

A degree of freedom is a way the gas can store energy that can be expressed as expression involving the square of some variable, and the average energy in this degree of freedom is simply kT/2.
 
So was the Question on the MCAT asking how many degrees of freedom there are??/ and if so how do we determine that. Or did it give the degree of freedom and want to know the energy in which case we use kt/2?
 
Thanks guys. Do you think we would need to know how to figure out the degrees of freedom a molecule has? I understand the basic definition but the full concept.
 
I think a basic understanding should suffice. They may say, the energy of a gas is U = (7/2)NkT; how many degrees of freedom does this gas have? (Answer: 7).

In my experience, they didn't really test specific knowledge just your understanding of basic concepts and ability to reason your way through things.
 
I should also add that different modes may only be accessible if the temperature is above some threshold, so that for low temperature, only the translation modes are accessible so the gas behaves as though it has three degrees of freedom, but if you raise the temperature, the rotational modes become accessible and the gas behaves as though there are 5 degrees of freedom. Higher still you open up vibrational modes, and the gas behaves as if it has 7 degrees of freedom. I attached a terrible graph of the degrees of freedom (f/2 = U/(NkT)) versus T.
 

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