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Hi,
Question 92 in the B/B Section banks presents us with an enzyme called Glycerol Phosphorylase (GK), which is a "homo dimer". "assume that GK maintains a single state in solution"
The info above is all that is needed to answer the question.
The question asks to predict what would be observed on native vs SDS page.
The answer which I picked was 1 band for both which is the correct answer BUT, their explanation makes me have another question which is why I'm here.
My reasoning: Since both native and SDS page are done under NON reducing conditions (since it is not mentioned that a reductant was used or not, it is safe to assume non reducing), then if there exists any disulfide bonds they would remain intact and so our homodimer would travel as one in both cases albeit it would be unraveled in the SDS page, so, 1 band for both.
AAMC reasoning: Since it is a homodimer, if we disrupt the quaternary structure in SDS page they would travel as 1 band.
Okay this makes sense too, but why are they assuming that the SDS page would separate the sub-units? This would only happen if there were no disulfide bonds. The passage does not mention disulfide bonds at all (it does not rule them out, nor confirm them), but they are very common in quaternary structures to my limited knowledge.
Is it the case if that if no disulfide bonds are mentioned in the passage, we should assume that they do not exist, and that SDS page will always separate subunits of a multi dimeric protein?
Question 92 in the B/B Section banks presents us with an enzyme called Glycerol Phosphorylase (GK), which is a "homo dimer". "assume that GK maintains a single state in solution"
The info above is all that is needed to answer the question.
The question asks to predict what would be observed on native vs SDS page.
The answer which I picked was 1 band for both which is the correct answer BUT, their explanation makes me have another question which is why I'm here.
My reasoning: Since both native and SDS page are done under NON reducing conditions (since it is not mentioned that a reductant was used or not, it is safe to assume non reducing), then if there exists any disulfide bonds they would remain intact and so our homodimer would travel as one in both cases albeit it would be unraveled in the SDS page, so, 1 band for both.
AAMC reasoning: Since it is a homodimer, if we disrupt the quaternary structure in SDS page they would travel as 1 band.
Okay this makes sense too, but why are they assuming that the SDS page would separate the sub-units? This would only happen if there were no disulfide bonds. The passage does not mention disulfide bonds at all (it does not rule them out, nor confirm them), but they are very common in quaternary structures to my limited knowledge.
Is it the case if that if no disulfide bonds are mentioned in the passage, we should assume that they do not exist, and that SDS page will always separate subunits of a multi dimeric protein?