Question regarding solubility...

Started by akakakakak
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akakakakak

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What mass of H20 is needed to prepare 148 grams of 12% (m/m) KHCO3 solution)?
 
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Draw the Lewis structure of SO2, CO2, H2S and CH2Cl2, you will see that only CO2 is non polar (linear) and thus it is more soluble in benzene than water. AgCl is out of the question because it is ionic.
 
No problem
% m/m = (mass of solute/ mass of solution) * 100%.
A 12% m/m KHCO3 solution means for every 100 g of solution, you have 12 g KHCO3. So for 148 g solution, you need 12%*148g of solution/100% = 17.76 g of KHCO3.
The mass of water needed is 148 - 17.76 = 130.24 g
 
No problem
% m/m = (mass of solute/ mass of solution) * 100%.
A 12% m/m KHCO3 solution means for every 100 g of solution, you have 12 g KHCO3. So for 148 g solution, you need 12%*148g of solution/100% = 17.76 g of KHCO3.
The mass of water needed is 148 - 17.76 = 130.24 g
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