theedaddy77

10+ Year Member
May 9, 2008
113
0
Status
Pre-Dental
for oozenalysis, i know if you have a ethelyne, the reactants will take it to carbolxlic, but if you are starting with a 1-propene (3 carbons and there is a double bond in it) how do you know BASED ON REAGENTS if it will go to carboxlyix or aldeyde? . im not talking about kmno4 but the the ozone one.. thanks SDN!
 

userah

10+ Year Member
7+ Year Member
Aug 9, 2007
555
0
Status
Dental Student
to determine whether or not you will get carboxylic acid or aldehyde, gotta see if it's under oxidative conditions or reducing conditions. instead of possibly confusing you with my explanation, i'll just show you the website which explains in clear and concise manner. One which kaplan book doesn't do a very good job at might I add...haha

For alkene + ozone
http://www.chem.ucalgary.ca/courses/351/Carey5th/Ch06/ch6-10.html

for alkyne + ozone
http://www.chem.ucalgary.ca/courses/351/Carey5th/Ch09/ch9-11.html

hope that helps. let me know if you still need help
 
OP
T

theedaddy77

10+ Year Member
May 9, 2008
113
0
Status
Pre-Dental
so i looked at both sites and they were both helpful, but so reductive workup will be with a an acid but h202 wouldbe an oxidative workup so it will become 2 carboxlyix? Please hit me up when you get the chance, and thanks for the help!!!!
 

userah

10+ Year Member
7+ Year Member
Aug 9, 2007
555
0
Status
Dental Student
yup you got it. reductive workup by zinc and acetic acid will give you aldehydes while oxidative work up with hydrogen peroxide (h202) will give you carboxylic acids.