Quick chiral center question

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what gets a higher number of proirity. COOH group or the usual middle bond which is usually ch2ch2. Destroyer says ch2ch2 but achiever says COOH

Can you give me where it says on Destroyer that Ch2Ch2 has higher priority over COOH.

It depends on the molecular weight of what is attached to the chiral carbon

Based on your context, if COOH is one group attached to the chiral carbon, and ethyl being the other group, then COOH definitely gets the priority.
 
This is the THIRD time I've done this question and because I did not read the question carefully. I felt for the trap once again. (slap to the face)

Ok. I don't think $244 should trouble you at all.

like I mentioned, higher molecular wins. Everything is as it is how the answer key explains.

#230... Same thing happens. Yes the compound name should be (2R, 3S)-2-bromo-3-chlorobutanoic acid.... Based on our understanding of what gets the higher priority. However the quesitons asks for the ENANTIOMER of this. That is why it is choice C. Not that COOH had the priority over higher molecular weight Chlroine. Read the question carefully. I hope I don't make this mistake on my real DAT.

good luck on your DAT, I noticed you have it real soon.

P.S. Get off this forum until your exam lol. Someone had already mentioned to you. I've heard it is mentally stressful to be here right before exam time.
 
On #243,

With respect to Carbon #2

it has H, Cl, COOH, and "R" as answer key denotes

Obviously you see Cl is #1 - highest molecular weight

#2 priority is R because there is a tie with the first atom directly attached to Carbon #2. One is C-O-OH and the R group is C-Cl-H

Cl beats O in molecular weight so #2 priority is R group here
 
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