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What is the expression for the solubility product constant, Ksp, for BaCl2?
I thought we take into consideration that there are two Cl's because the reaction follows:
BaCl2 --> Ba^+2 + 2Cl-
Thus Ksp=[Ba^+2][Cl-]^2 ?
But the correct answer they give is Ksp=[Ba^+2][Cl-] (without the 2 exponent)
...and I believe there's something similar in the Kaplan book using BaF2 where they do include ^2 in Ksp answer.
Any ideas????
I thought we take into consideration that there are two Cl's because the reaction follows:
BaCl2 --> Ba^+2 + 2Cl-
Thus Ksp=[Ba^+2][Cl-]^2 ?
But the correct answer they give is Ksp=[Ba^+2][Cl-] (without the 2 exponent)
...and I believe there's something similar in the Kaplan book using BaF2 where they do include ^2 in Ksp answer.
Any ideas????